# Codeforces - 1166B - All the Vowels Please

## 地址

http://codeforces.com/contest/1166/problem/B

## 原文地址

https://www.lucien.ink/archives/431

## 题目

Tom loves vowels, and he likes long words with many vowels. His favorite words are vowelly words. We say a word of length $k$ is vowelly if there are positive integers $n$ and $m$ such that $n\cdot m = k$ and when the word is written by using $n$ rows and $m$ columns (the first row is filled first, then the second and so on, with each row filled from left to right), every vowel of the English alphabet appears at least once in every row and every column.

You are given an integer $k$ and you must either print a vowelly word of length $k$ or print $-1$ if no such word exists.

In this problem the vowels of the English alphabet are 'a', 'e', 'i', 'o' ,'u'.

## 题解

### 代码

https://pasteme.cn/8171

#include <bits/stdc++.h>
int n, x = -1, y = -1;
char ans[int(1e5) + 7];
int index(int a, int b) {
return a * y + b;
}
char table[] = "aeiou";
void solve(int a) {
for (int j = 0; j < y; j++) {
ans[index(a, j)] = table[(a + j) % 5];
}
}
int main() {
scanf("%d", &n);
for (int i = 1; i * i <= n; i++) {
if (n % i == 0) {
if (i >= 5 && n / i >= 5) {
x = i, y = n / i;
break;
}
}
}
if (x < 0 || y < 0) return 0 * puts("-1");
for (int i = 0; i < x; i++) {
solve(i);
}
for (int i = 0; i < x; i++) {
for (int j = 0; j < y; j++) {
printf("%c", ans[index(i, j)]);
}
}
putchar('\n');
return 0;
}